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15y^2-31y-24=0
a = 15; b = -31; c = -24;
Δ = b2-4ac
Δ = -312-4·15·(-24)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-49}{2*15}=\frac{-18}{30} =-3/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+49}{2*15}=\frac{80}{30} =2+2/3 $
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